What mass of carbon dioxide can 1.00 kg of lithium oxide absorb?

Question

Serenity Allen · Accepted Answer

The LiOH can absorb 920 g of carbon dioxide.

The equation that is balanced is #"2LiOH" + "CO"_2 → "Li"_2"CO"_3 + "H"_2"O"# The following conversions are necessary: #"mass of LiOH" → "moles of LiOH" → "moles of CO"_2 → "mass of CO"_2# #1.00 × 10^3 color(red)(cancel(color(black)("g LiOH"))) × "1 mol LiOH"/(23.95 color(red)(cancel(color(black)("g LiOH")))) = "41.8 mol LiOH"# #41.8 color(red)(cancel(color(black)("mol LiOH"))) × ("1 mol CO"_2)/(2 color(red)(cancel(color(black)("mol LiOH")))) = "20.9 mol CO"_2# #20.9 color(red)(cancel(color(black)("mol CO"_2))) × ("44.01 g CO"_2)/(1 color(red)(cancel(color(black)("mol CO"_2)))) = "920 g CO"_2#

Axel Alvarado · Answer

undefined To determine the mass of carbon dioxide that 1.00 kg of lithium oxide can absorb, we first need to find the molar mass of lithium oxide (Li2O) and carbon dioxide (CO2).

The molar mass of Li2O is approximately 29.88 g/mol (6.94 g/mol for lithium + 15.999 g/mol for oxygen).

The molar mass of CO2 is approximately 44.01 g/mol (12.01 g/mol for carbon + 2 * 15.999 g/mol for oxygen).

Next, we need to find the molar ratio between lithium oxide and carbon dioxide. This ratio is 1:1 according to the balanced chemical equation:

Li2O + CO2 → Li2CO3

Since the molar ratio is 1:1, for every 1 mole of Li2O, 1 mole of CO2 is absorbed.

Now, we can calculate the mass of CO2 absorbed by 1.00 kg (1000 g) of Li2O:

1. Determine the number of moles of Li2O:
   Moles of Li2O = Mass of Li2O / Molar mass of Li2O
                  = 1000 g / 29.88 g/mol
                  ≈ 33.47 mol

2. Since the molar ratio is 1:1, the number of moles of CO2 absorbed is also 33.47 mol.

3. Calculate the mass of CO2:
   Mass of CO2 = Number of moles of CO2 * Molar mass of CO2
               = 33.47 mol * 44.01 g/mol
               ≈ 1475.83 g

Therefore, 1.00 kg of lithium oxide can absorb approximately 1475.83 grams of carbon dioxide.