#2NaN_3(s) - 2Na(s) + 3N_2(g)# Given the equation, how many moles of #N_2# are produced by the decomposition of 1.50 mol of #NaN_3#?

Question

#2NaN_3(s) -> 2Na(s) + 3N_2(g)#  Given the equation, how many moles of #N_2# are produced by the decomposition of 1.50 mol of #NaN_3#?

Mateo Aguilar · Accepted Answer

2.25mol.

The equation tells you that for every 2 moles of #NaN_3# decomposed, you get 3 moles of #N_2# out. Thus, just divide the 1.5 mol by two and multiply the result by three.

Cooper Anderson · Answer

undefined 2.25 mol of N₂ is produced from 1.50 mol of NaN₃.

HIX Tutor · Answer

undefined Great question! Let's break it down step by step.

1. **Look at the equation**: 2NaN₃(s) → 2Na(s) + 3N₂(g)

2. **Find the mole ratio**: From the equation, we see that 2 moles of NaN₃ produce 3 moles of N₂.

3. **Set up the ratio**: 
   $$
   \text{If } 2 \text{ moles of NaN}_3 \text{ produce } 3 \text{ moles of N}_2,
   $$
   what do you think happens if you have 1.50 moles of NaN₃?

4. **Use a proportion**: 
   $$
   \frac{3 \text{ moles N}_2}{2 \text{ moles NaN}_3} = \frac{x \text{ moles N}_2}{1.50 \text{ moles NaN}_3}
   $$

5. **Cross-multiply**:
   $$
   3 \cdot 1.50 = 2 \cdot x
   $$
   $$
   4.5 = 2x
   $$

6. **Solve for x**:
   $$
   x = \frac{4.5}{2} = 2.25
   $$

7. **Conclusion**: So, 1.50 moles of NaN₃ produce **2.25 moles of N₂**.

Does that make sense?

#2NaN_3(s) -&gt; 2Na(s) + 3N_2(g)# Given the equation, how many moles of #N_2# are produced by the decomposition of 1.50 mol of #NaN_3#?

#2NaN_3(s) -> 2Na(s) + 3N_2(g)# Given the equation, how many moles of #N_2# are produced by the decomposition of 1.50 mol of #NaN_3#?