√26 =? for class 7

Answer 1

#sqrt(26)~~5.099#

Given: #sqrt(26)# for class #7#
I'm not sure what you mean for class #7#. I'm assuming you want to find the #sqrt(26)# without a calculator.

First look at perfect squares:

#sqrt(25) = 5; " " sqrt(36) = 6#
Since #26# is closest to #25#, we know that the #sqrt(26)# must be larger than #5#, but fairly close to #5# rather than #6#.
Start by multiplying #5.1 xx 5.1#:
#5.1 xx 5.1 = 26.01#
Since #26.01# is very close to #26# this means that #sqrt(26)# must be slightly less than #5.1#
Start iterating until you get closer to #26#:
#5.05 xx 5.05 = 25.5026# #5.08 xx 5.08 = 25.8064# #5.09 xx 5.09 = 25.9081# #5.095 xx 5.95 = 25.959025# #5.098 xx 5.98 = 25.989604# #5.099 xx 5.99 = 25.999801#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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