Find the components of the resultant force on it along&perpendicular to the string?

Two similar balls, having charge +q and mass m gram are suspended from a common point by two insulating strings l meters long. The balls are held at a separation l/10 apart and released.

Answer 1

We draw a free-body diagram for one of the charged balls, say left. This is shown in the figure below.

All the forces acting on the charged ball are in equilibrium.

It is not given clearly but assumed that the system is in equilibrium when distance between the charged balls is #=l/10#
Therefore, distance between vertical drawn from common hanging point and each ball is #l/20#

One force is tension #T# in the insulating string. The other force is weight #mg# of ball acting downward and third is electrostatic force of repulsion #F_"elec"# between the two charged balls.

#F_"elec"=k_eq^2/(l/10)^2=(100k_eq^2)/l^2#
where #k_e# is Coulomb's Constant

It is clear from geometry that

  1. #sintheta=(l/20)/l=1/20=0.05#
    and
  2. #costheta=sqrt(1-sin^2theta)=sqrt(1-1/20^2)=0.9987#

  3. Component of weight along the string#=mgcostheta#
    Component of weight perpendicular to the string#=mgsintheta#

  4. Component of tension along the string#=T#
    Component of tension perpendicular to the string#=0#

  5. Component of electrostatic force along the string#=(100k_eq^2)/l^2sin theta#
    Component of electrostatic force perpendicular to the string#=(100k_eq^2)/l^2cos theta#

    From (1) to (5) in the case of all forces being in equilibrium we get
    #T=0.9987mg+0.05(100k_eq^2)/l^2#

    #T=0.9987mg+(5k_eq^2)/l^2# .....(1)

    #0.05mg=0.9987(100k_eq^2)/l^2#

    #mg=(1997.5k_eq^2)/l^2# ......(2)

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Answer 2

To find the components of the resultant force along and perpendicular to the string, you would need to break down the resultant force vector into its horizontal and vertical components using trigonometric functions such as sine and cosine. The component along the string direction is typically found using cosine, and the component perpendicular to the string direction is found using sine. Once you have the angles involved and the magnitude of the resultant force, you can calculate the components accordingly.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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