10 g of Cu, 10 g of O2 react. Which is the limiting reactant? What amount of reactant remains in excess? Calculate the number of particles of reactant in excess. What is the mass of the produced product?

Answer 1

Cu is the limiting reactant
#5 g " "O_2# in excess
#~~15 g " "CuO_2# produced

Given: #10# g Cu reacts with #10# g #O_2#.
Skeletal equation: #" "Cu + O_2 -> CuO_2#

balanced equation is the same as the skeletal equation.

molar masses:

#63.546 g/(mol) " "Cu; " " 2(15.999) = 31.998 g/(mol) " "O_2#
#63.546 + 31.998 = 95.544 g/(mol) " "CuO_2#

Find the limiting reagent:

#10 g Cu xx (1 mol Cu)/(63.546 g Cu) xx (1 mol CuO_2)/(1 mol Cu) = .1574 mol " " CuO_2#
#10 g O_2 xx (1 mol O_2)/(31.998g O_2) xx (1 mol CuO_2)/(1 mol Cu) = .1325 mol " " CuO_2#

Cu is the limiting reagent.

#O_2# is in excess.
Find the amount of #O_2# used: #.1574 mol " " CuO_2 xx (1 mol O_2)/(1 mol CuO_2) xx (31.998 g O_2)/(1 mol O_2) ~~ 5 g " "O_2 #
Find the mass of #O_2# in excess: #10 g - 5 g ("used")= 5 g# in excess
Find the mass of produced product #CuO_2#:
#.1574 mol " " CuO_2 xx (95.544 g CuO_2)/(1 mol CuO_2) = 15.04 g " "CuO_2#
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Answer 2

To determine the limiting reactant, we first need to calculate the number of moles for each reactant. Then, we compare the moles of each reactant to the stoichiometric coefficients in the balanced chemical equation to find which one is consumed first. The reactant that produces fewer moles of product is the limiting reactant.

After identifying the limiting reactant, we can calculate the amount of the other reactant that remains in excess by subtracting the amount reacted from the initial amount.

To calculate the number of particles of the reactant in excess, we convert the remaining amount of the excess reactant to moles, then use Avogadro's number to find the number of particles.

Finally, to find the mass of the product produced, we use the stoichiometry of the balanced chemical equation to relate the moles of the limiting reactant to the moles of the product, and then convert moles to grams using the molar mass of the product.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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