10.00mg of a substance yields 11.53mg H2O and 28.16mg CO2. What is the empirical formula of menthol? This is so confusing, help would be much appreciated!?

Answer 1

Empirical formula: #C_"10"H_"20"O#. It corresponds to the empirical and molecular formula of menthol.

In other words, #C_"10"H_"20"O_1#, or #C_"10"H_"20"O#.

Additionally, menthol has this molecular formula.

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Answer 2

In order to find the empirical formula of menthol, we must first calculate the simplest whole-number ratio of the elements by finding the moles of each element present in the given compounds (H2O and CO2). Next, we must compute the moles of hydrogen (H) and carbon (C) in the given compounds: - Moles of H2O = 11.53 mg / molar mass of H2O - Moles of CO2 = 28.16 mg / molar mass of CO2 3. Calculate the ratio of moles of hydrogen to carbon. 4. Write the empirical formula using the determined whole-number ratio of elements. 5. Finally, confirm that the ratio obtained is valid by ensuring it represents the actual ratio of elements in menthol.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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