0.550 moles of NaCl are dissolved in 1.95 L of water. Calculate the molarity of the NaCl solution. ?

Answer 1

#[NaCl(aq)]=0.282*mol*L^-1#

We assume reasonably that the volume of the solvent remains constant during dissolution....and so we simply take the quotient...

#"[NaCl]"="moles of salt (mol)"/"volume of solution (L)"=(0.550*mol)/(1.95*L)#

#-=??*mol*L^-1#...what are the concentrations with respect to #Na^+# and #Cl^-#?

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Answer 2

Natalie Anton

Molarity (M) is calculated using the formula:

Molarity = moles of solute / volume of solution (in liters)

Given: Moles of NaCl (solute) = 0.550 moles Volume of solution (water) = 1.95 L

Using the formula:

Molarity = 0.550 moles / 1.95 L

Molarity ≈ 0.282 M

Therefore, the molarity of the NaCl solution is approximately 0.282 M.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.